XL=ωL=100x0.1=10Ω，Xc=1/ωC=1/100x0.001=10Ω
IRL=10/√(10^2+10^2)=1/√2A
P=I^2xR=0.5x10=5W
QL=I^2xXL=0.5x10=5Var
Qc=U^2/Xc=100/10=10Var
总Q=QL-Qc=5-10=-5Var
S=√(P^2+Q^2)=√2x5VA
I=S/U=√2x5/10=√2/2A
由于电路为容性负载，φ=arctgP/Q=45º，电流超前电压45度，
i=(√2/2)√2sin(100t+45º)=2sin(100t+45º)A
