先给你一个正确的方法：
1，把bean里面的get方法上面的格式去掉
我的代码如下：
private Timestamp time;
public Timestamp getTime() {
return time;
}
public void setTime(Timestamp time) {
this.time = time;
}
测试方法：
public static void main(String[] args) throws JsonProcessingException, ParseException {
Timestamp timestamp = new Timestamp(System.currentTimeMillis());
AccountInfo accountInfo = new AccountInfo();
accountInfo.setTime(timestamp);
ObjectMapper mapper = new ObjectMapper();
mapper.setDateFormat(new SimpleDateFormat("yyyy-MM-dd hh:mm:ss"));
String s = mapper.writeValueAsString(accountInfo);
System.out.println(s);
long time = DateUtils.parseDate("1987-06-04 00:00:001","yyyy-MM-dd hh:mm:ss").getTime();
String date = DateUtils.parseDate("1987-06-04 00:00:01","yyyy-MM-dd hh:mm:ss").toString();
System.out.println(date);
timestamp = Timestamp.valueOf("1987-06-04 00:00:00");
System.out.println(timestamp);
accountInfo = new AccountInfo();
accountInfo.setTime(timestamp);
mapper = new ObjectMapper();
mapper.setDateFormat(new SimpleDateFormat("yyyy-MM-dd hh:mm:ss"));
s = mapper.writeValueAsString(accountInfo);
System.out.println(s);
}输出结果：
{"openId":null,"token":null,"ip":null,"account":null,"phone":null,"email":null,"platformType":0,"time":"2018-10-16 01:27:16"}
Thu Jun 04 00:00:01 CDT 1987
1987-06-04 00:00:00.0
{"openId":null,"token":null,"ip":null,"account":null,"phone":null,"email":null,"platformType":0,"time":"1987-06-04 12:00:00"}不过这里有一个小问题，因为你是使用的yyyy-MM-dd hh:mm:ss 格式，而hh表示按12小时计时，所以1987-06-04 00:00:00会在json中表示为1987-06-04 12:00:00，你可以换成yyyy-MM-dd HH:mm:ss按24小时计进即可。
