i3=i1+i2
6=(510+510)i1+510i3=1530i1+510i2.........(1)
12=(1000+330)i2+510i3=1840i2+510i1.......(2)
(2)- (1)x2 0=820i2-2550i1,i1=82/255 i2=0.322i2,
6=1530(0.322i2)+510i2=1002.66i2,i2=5.99mA,i1=1.9mA,i3=7.9mA
Uab=510i3=4.03v,Ubd=330i2=1.98v,Udc=-12v,Uca=1000i2=5.99v。