①根据燃烧热概念,结合热化学方程式,2H
2(g)+O
2(g)=2H
2O (l)△H=-571.6kJ/mol,氢气的燃烧热为:H
2(g)+
O
2(g)=H
2O (l)△H=-285.8kJ/mol,所以氢气的燃烧热为285.8KJ/mol,故答案为:-285.8KJ/mol;
②(1)CO(g)+2H
2(g)?CH
3OH(g)△H=-90.8kJ/mol,(2)H
2(g)+
O
2(g)=H
2O(g)△H=-241.8kJ/mol;
(2)×2-(1)得到:CH
3OH(g)+O
2(g)?CO(g)+2H
2O(g)△H=-392.8 kJ/mol,
故答案为:-392.8 kJ/mol.